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Jim paddles from one shore of a lake 3 miles wide at 4 mph, and John paddles from the opposite shore at 5 mph. How long will they travel before they meet?

User Rui Vieira
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recall your d = rt, distance = rate * time.

the lake is only 3 miles wide, and these guys are really fast.

now, when Jim and John meet, Jim has covered say "d" miles, and John has covered by then, the slack from 3 and d, namely "3 - d", the lake is only 3 miles wide.

By the time they meet, Jim has been paddling "t" hours, and John has been paddling "t" hours as well, because both started at the same time, though John with the faster rate, covered more ground.


\bf \begin{array}{lccclll} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ &------&------&------\\ Jim&d&4&t\\ John&3-d&5&t \end{array} \\\\\\ \begin{cases} \boxed{d}=4t\\ 3-d=5t\\ ------\\ 3-\boxed{4t}=5t \end{cases} \\\\\\ 3=9t\implies \cfrac{3}{9}=t\implies \stackrel{hours}{\cfrac{1}{3}}=t\implies \stackrel{minutes}{20}
User Isak La Fleur
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