43.5k views
4 votes
The image shows a geometric representation of the function f(x)=x^2-2x-6 written in standard form. What is the function written in vertex form?

User Ivan Popov
by
7.4k points

2 Answers

5 votes
y=(x-1)^2-7 This is this function in vertex form
User Hugeen
by
7.6k points
6 votes

Answer:


y=(x-1)^2-7

Explanation:

Given : Equation =
f(x)=x^2-2x-6

To write in vertex form

Vertex form =
y = a(x - h)^2+ k

The given equation is in standard form
y=x^2-2x-6

to convert into vertex form we can use completing the square,

step 1 :
y=x^2-2x-6

step 2 :
y+6=x^2-2x

step 3 :
y+6+1=x^2-2x+1

step 4 :
y+7=(x-1)^2

step 5 :
y=(x-1)^2-7

It is a vertex form where a=1, h=1 , k=-7


User Rich P
by
7.6k points