Question

What is the equation of a line that goes through the point(0, 5/6) and has a slope of 1?

Answer 1

Using the point-slope formula in order to obtain the equation of the line.

The formula is,

`y-y_1=m\left(x-x_1\right)`

Given:

`\begin{gathered} \lparen x_1,y_1)=\left(0,(5)/(6)\right) \\ m=1 \end{gathered}`

Therefore,

`y-(5)/(6)=1\left(x-0\right)`

Simplify

`\begin{gathered} y-(5)/(6)=1\left(x\right) \\ y-(5)/(6)=x \\ \therefore y=x+(5)/(6) \end{gathered}`

Hence, the equation is

`y=x+(5)/(6)\text{ \lparen OPTION 1\rparen}`