Question

Find the equation of a line parallel to the given point. Write the equation in slope-intercept form Line y= -3x+ 6, point(1,-5)

Answer 1

Given:

`\text{ line }y=-3x+6\text{ and point (1,-5).}`

Aim:

We need to find the line which is parallel to y=-3x+6.

Step-by-step explanation:

We know that the slope of the parallel lines is equal.

The given line is of the form

`y=mx+b_1`
`\text{where }m=-3\text{ and }b_1=6.`

The slope of the required line is -3.

The slope-intercept form of the line equation for the required line is

`y=mx+b`

substitute m=-3, x=1, and y=-5 in the equation to find the value of b.

`-5=-3(1)+b`

`-5+3=b`
`b=-2`

Substitute m=-3 and b= -2 in the slope intercept line equation.

`y=(-3)x+(-2)`

`y=-3x-2`

Final answer:

Teh slope-intercept equation is

`y=-3x-2`