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Given the regular hexagon, find the measure of each numbered angle.

Given the regular hexagon, find the measure of each numbered angle.-example-1

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I believe that the answer would be C. because each triangle that is “broken up” in the hexagon is equilateral meaning that angle 1 and angle 3 would be congruent and equal to 60, and since angle 2 is half the measure of angle 1 it would be 30. Hope this helps!
User Maxqueue
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Answer:

m∠1=60°, m∠2=30°, m∠3=60°

Option C is correct.

Explanation:

Given a regular hexagon

we have to find the measure of ∠1, ∠2 and ∠3

As the angle formed at the centre of circle is 360° and the diagonals of hexagon divides the hexagon into 6 congruent triangles implies the angle at the centre of these 6 congruent triangles are equal.


\angle 1 =(360)/(6)=60^(\circ)

In ΔFOE, by angle sum property

∠FOE+∠OEF+∠3=180°

60°+2∠3=180° (∵ OF=OE both are radius)

2∠3=120°

∠3=60°

⇒ ΔFOE is equilateral triangle.

Hence, all 6 are equilateral triangles

In ΔOGD, by angle sum property

∠2+∠OGD+∠ODG=180°

∠2+90°+60°=180

∠2=30°

∠1=60°, ∠2=30°, ∠3=60°

Hence, option C is correct.

Given the regular hexagon, find the measure of each numbered angle.-example-1
User Amina
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