Question

suppose that YM has a length 12 in. and its distance from point L is 5in. find the radius of L to the nearest tenth

Answer 1

check the picture below.

Answer 2

The radius of circle L is
`7.8\ in`

Explanation:

we know that

In the figure the triangle VLM is a right triangle, because VL is pependicular to YM

so

`YV=VM=12/2=6\ in`

LM is the radius of the circle (hypotenuse of triangle VLM)

`VL=5\ in`

Applying the Pythagoras Theorem

`LM^(2)=VM^(2)+VL^(2)`

substitute

`LM^(2)=6^(2)+5^(2)`

`LM^(2)=61`

`LM=7.8\ in` ------> is the radius