X^2/3-3x^1/3-4=0 {x}^{ (2)/(3) } - {3x}^{ (1)/(3) } - 4 = 0

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asked May 12, 2018 59.4k views

4 votes

X^2/3-3x^1/3-4=0

${x}^{ (2)/(3) } - {3x}^{ (1)/(3) } - 4 = 0$

$X^2/3-3x^1/3-4=0 {x}^{ (2)/(3) } - {3x}^{ (1)/(3) } - 4 = 0-example-1$

Mathematics
middle-school

Vihana Kewalramani asked

by Vihana Kewalramani

8.6k points

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1 Answer

3 votes

${x}^{ (2)/(3) } - {3x}^{ (1)/(3) } - 4 = 0$
Solve using substitution

${t}^(2) - 3t - 4 = 0$
Solve the equation

$t = 4 \\ t = - 1$
Return the substituted values

${x}^{ (1)/(3) } = 4 \\ {x}^{ (1)/(3) } = - 1$
Solve the equations

$x = 64 \\ x = - 1$
The final solutions are,

$x1 = - 1 \\ x2 = 64$

Egan Wolf answered May 18, 2018