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Verify the identity. cos (x - y) - cos (x + y) = 2 sin x sin y

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Let's start from the left side, and manipulate it to get the right side, which would prove the identity.

We know that:

i)
\displaystyle{ \cos(x-y)=\cos x \cos y+\sin x \sin y

ii)
\displaystyle{ \cos(x+y)=\cos x \cos y-\sin x \sin y.

From the above fundamental identities, we can rewrite the left hand side as:


\displaystyle{ \cos x \cos y+\sin x \sin y-(\cos x \cos y-\sin x \sin y)=



\displaystyle{ \cos x \cos y+\sin x \sin y-\cos x \cos y+\sin x \sin y=2\sin x \sin y,

which is what we needed to show.
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