Question

Given. Two pair of values x1=5,y1=4,x2=1,y2=1/2. Calculate the Pythagorean triples associated with each pair?

Answer 1

We are giving two pairs of values for x and y. To calculate the Pythagorean triples for each pair, we need to focus on each pair individually.

a. x1 = 5, y1 = 4

Answer: sq(5^2 + 4^2) = sq(41)

b. x2 = 1, y2 = ?

Answer: r = sq(1^2 + ?^2)

Answer 2

the so-called pythagorean triple will just be the distance between both points,





`\bf d=\sqrt{(1-5)^2+\left( (1)/(2)-4 \right)^2}\implies d=\sqrt{(-4)^2+\left( -(7)/(2) \right)^2} \\\\\\ d=\sqrt{16+(7^2)/(2^2)}\implies d=\sqrt{16+(49)/(4)}\implies d=\sqrt{(64+49)/(4)} \\\\\\ d=\sqrt{(113)/(4)}\implies d=\cfrac{√(113)}{√(4)}\implies d=\cfrac{√(113)}{2}`