Question

What is the equation of the following line written in slope-intercept form?

A.) y =3/2 x -13/3
B.) y =2/3 x -13/3
C.) y =-2/3x - 13/3

Answer 1

B. y=2/3x-13/3 is written in slope intersept form

Answer 2

WE use given graph to find equation of the line

one point on the graph is (-5,-1)

other point on the graph is (-2,-3)

We need to frame equation y =mx+b

Lets find slope using (-5,-1) and (-2,3)

`slope m = (y^2-y_1)/(x_2-x_1) = (-3-(-1))/(-2-(-5)) =(-2)/(3)`

Now we find y intercept b using (-5,-1)

y=mx+b

`-1= (-2)/(3)(-5) + b`

`-1= (10)/(3)+b`

Subtract 10/3 on both sides

`-1 - (10)/(3)=b`

`(-13)/(3)=b`

So equation of the line is
`y=(-2)/(3)x-(13)/(3)`