Question

You are serving bratwurst and hamburgers at your annual picnic. You want at least three bratwursts or hamburgers for each of your 50 guests. Bratwursts cost $1.25 each and hamburgers $0.95 each. Your budget is $200

let x be the number of bratwursts and y the number of hamburgers. which system of inequalities represents this situation?

Answer 1

x+y>=120 1.35x+1.2<=175

That's the logical interpretation of this scenario

Answer 2

`x+y\geq 150`

`1.25x+0.95y\leq 200`

Explanation:

Let no. of bratwursts be x

Let no. of hamburgers be y

We are given that You want at least three food items for each of the 50 guests.

This means you want at least
`3(50) = 150` bratwursts or hamburgers.

So, equation becomes:
`x+y\geq 150`

Now Bratwursts cost $1.25 each

So, Cost of x bratwursts is 1.25 x

Cost of 1 hamburger is $0.95

Cost of y hamburgers = 0.95y

Your budget is $200

So, you cannot afford the bill more than 200

So, equation becomes:
`1.25x+0.95y\leq 200`

Hence system of inequalities represents this situation is
`x+y\geq 150` and
`1.25x+0.95y\leq 200`