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Compound a has a molecular formula c5h12, and monobromination of compound a produces only compound

b. when compound b is treated with a strong base, a mixture is obtained containing compound c and compound
d.

User TedBurrows
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Final answer:

Compound A with the molecular formula C5H12 undergoes monobromination to produce compound B. When compound B is treated with a strong base, a mixture containing compound C and compound D is obtained.

Step-by-step explanation:

Compound A, with the molecular formula C5H12, undergoes monobromination to produce compound B. When compound B is treated with a strong base, it forms a mixture containing compound C and compound D. The molecular formula C5H12 indicates that compound A consists of 5 carbon atoms and 12 hydrogen atoms. Monobromination of compound A produces only compound B, so compound B must have the same molecular formula C5H12 as compound A. When compound B is treated with a strong base, it forms a mixture containing compound C and compound D.

User Will Ray
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From my understanding, bromination, chlorination, etc. is s chemical chain reaction in which the Hs are substitutes with the halogen after the diatomic molecule breaks.

In laments terms, the reaction looks like this

C5H12 + Br2 —> C5H11Br + HBr
User Fahim Bagar
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