Question

What is the approximate radius of a 112 48 cd nucleus?

Answer 1

What is it comparing it to?

2√3 = 1.26 times as large

Answer 2

radius of a
`^(112)Cd_(12)` nucleus is 5.784×
`10^(-15)` meters

Explanation:

Since radius of a nucleus is measured by the formula

R =
`R_(0)(A)^{(1)/(3) }`

Where
`R_(0)` is the average radius of a nucleus. This radius varies with the size of nucleons.

In this formula A = number of nucleons = (Number of protons + neutrons)

For element Cd number of nucleons = 112

and
`R_(0)` = 1.2×
`10^(-15)`

Now we put these values in the given formula

R =
`1.2* 10^(-15)*(112)^{(1)/(3)}`

=
`1.2* 10^(-15)*4.82`

= 5.784×
`10^(-15)` meters

Therefore, radius of a
`^(112)Cd_(12)` nucleus is 5.784×
`10^(-15)` meters