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Simplify cube root of 7 / Fifth root of 7

A. 7 to the power of 1 over 5
B. 7 to the power of 8 over 15
C. 7 to the power of 5 over 3
D. 7 to the power of 2 over 15

User Jonathanb
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2 Answers

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7^(1/3) : 7^( 1/5)= 7^(1/3 -1/5)=7^[(5-3)/15]= 7^[2/15]

the answer is D
User Martin Pabst
by
8.6k points
4 votes

Answer:

Option D. is the answer.

Explanation:

we have to simplify the cube root of
\frac{\sqrt[3]{7}}{\sqrt[5]{7} }

=
\frac{7^{(1)/(3)}}{7^{(1)/(5) } }

=
7^{(1)/(3)-(1)/(5)}

=
7^{((5-3)/(15))}

=
7^{(2)/(15)}

Therefore, Option D. 7 to the power of 2 over 15 is the answer.

User MokiSRB
by
7.0k points

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