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If a salesperson sells 3/4 of an acre for $80,000, what was the price per square foot rounded to two decimal spaces?

User Lazaros
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now, recalling that for 1 yard, there are 3 feet, therefore
\bf \begin{array}{ll} yards&feet\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 1yd&3ft\\ (1yd)^2&(3ft)^2\\ yd^2&3^2ft^2\\ &9ft^2 \end{array}

and keeping in mind that, there are 4840 yd² in 1 acre, then


\bf \cfrac{\quad (3)/(4)~\underline{acre}\quad }{80000~\$}\cdot \cfrac{4840~\underline{yd^2}}{\underline{acre}}\cdot \cfrac{9~ft^2}{\underline{yd^2}}\implies \cfrac{(3)/(4)\cdot4840\cdot 9~ft^2}{80000~\$}\implies \cfrac{(130680)/(4)}{80000} \\\\\\ \cfrac{(130680)/(4)}{(80000)/(1)}\implies \cfrac{130680}{4}\cdot \cfrac{1}{80000}\implies \cfrac{3267}{8000}~(ft^2)/(\$)~\approx~ 0.408375 ~(ft^2)/(\$)
User Dodzi Dzakuma
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