Question

In a group of 25 students, 12 students play basketball, 11 students play football. Five students play both sports. A student is chosen randomly from this group. What is the probability that the student plays both basketball or football?

Answer 1

P(student plays both basketball or football)=18/25

Explanation:

We are given that:

In a group of 25 students, 12 students play basketball, 11 students play football. Five students play both sports.

Now, A student is chosen randomly from this group.

What is the probability that the student plays both basketball or football?

Probability of any event=no. of favorable outcomes/total no. of outcomes

Here, no. of favorable outcomes

=no. of students who plays both basketball or football

= 12+11-5

= 18

and, total no. of outcomes=25

Hence, P(student plays both basketball or football)=18/25