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3 votes
N △JKL, KN=21 m.
What is the length of KX?

N △JKL, KN=21 m. What is the length of KX?-example-1
User Prakash S
by
7.9k points

2 Answers

3 votes

Answer:


KX = 14m

Explanation:

To solve this problem, we need to use the theorem about the intersection of all three medians, which states

"The medians of a triangle concurrent at a point that is two-thirds from each vertex to the mid point at the opposite side".

If we apply this theorem, we have


KX = (2)/(3)KN

So, if
KN = 21 m

Then,


KX = (2)/(3)21m=14m

Therefore,


KX = 14m

User Noamiko
by
7.6k points
5 votes

KX = 2/3(21)

KX = 14 m

User ChuckJHardy
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8.0k points