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1 vote
Write an equation in point-slope form.

(8,3); m=6

possible answers-
y+3=6(x-8)
y-3=6(x+8)
y-3=6(x-8)
y+3=6x-8


second question with the same directions-

(-3,-5); m=-2/5

y+5=-2/5(x+3)
y+5=(-2/5)x+3
y-5=-2/5(x+3)
y-5=2/5(x-3)

1 Answer

1 vote
first: let (8,3) be the coordinates of the point A
so equation of straight: y-yA=slope(x-xA)
y-3=6(x-8)
second: y-yB=slope(x-xB)
y-(-5)=-2/5(x-(-3))
y+5=-2/5(x+3)
User Ignarukih
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