Question

What is the range of the function f(x) = 4x + 9, given the domain D = {-4, -2, 0, 2}?

Answer 1

F(-4)=4*(-4)+9=-16+9=-7

F(-2)=4*(-2)+9=-8+9=1

F(0)=4*0+9=0+9=9

F(2)=4*2+9=8+9=17

Answer 2

The range of the function for given domain is R = { -7,1,9,17}.

Explanation:

The given function is

`f(x)=4x+9`

The given domain is D = {-4, -2, 0, 2}.

Substitute x=-4 in the given equation.

`f(-4)=4(-4)+9=-16+9=-7`

Substitute x=-2 in the given equation.

`f(-2)=4(-2)+9=-8+9=1`

Substitute x=0 in the given equation.

`f(0)=4(0)+9=0+9=9`

Substitute x=2 in the given equation.

`f(2)=4(2)+9=8+9=17`

Therefore the range of the function for given domain is R = { -7,1,9,17}.