Question

Calculate the time needed to accelerate a 40 kg object from 2 m/s to 12 m/s if a force of 8 N is applied. a 400 seconds b 10 seconds c 50 seconds d 0.2 seconds

Answer 1

The answer is C. 50 s

Given: M = 40 Kg; Vi = 2 m/s; Vf = 12 m/s; F = 8 N

Formula: F = ma but a = Vf - Vi/t substitute acceleration "a" from F = ma

F = m(Vf - Vi)/t Solve for time "t" t = m(Vf - Vi)/F

t = 40 Kg (12 m/s - 2 m/s)/8 Kg.m/s²

t = 50 s