Question

Divide −5 5/6÷(−2 1/6)

Answer 1

Assuming you mean

`-5\cdot ((5)/(6))/(-2\left((1)/(6)\right))`
Lets begin!

First remove the parenthesis

`((5)/(6))/(-2\cdot (1)/(6))`


`\mathrm{Apply\:the\:fraction\:rule}: (a)/(-b)=-(a)/(b) \ \textgreater \ -((5)/(6))/(2\cdot (1)/(6))`


`\mathrm{Apply\:the\:fraction\:rule}: ((b)/(c))/(a)=(b)/(c\:\cdot \:a) \ \textgreater \ ((5)/(6))/(2\cdot (1)/(6))=(5)/(2\cdot \:6\cdot (1)/(6)) \ \textgreater \ -(5)/(2\cdot \:6\cdot (1)/(6))`

Now simply multiply the numbers

`-(5)/(12\cdot (1)/(6))`

Now we have

`-5\left(-(5)/(12\cdot (1)/(6))\right)`


`\mathrm{Apply\:rule}\:-\left(-a\right)=a \ \textgreater \ 5\cdot (5)/(12\cdot (1)/(6))`


`\mathrm{Multiply\:fractions}: \:a\cdot (b)/(c)=(a\:\cdot \:b)/(c) \ \textgreater \ (5\cdot \:5)/(12\cdot (1)/(6))`

Multiply the numbers again

`(25)/(12\cdot (1)/(6))`

Lets break down the denominator

`12\cdot (1)/(6)`


`\mathrm{Multiply\:fractions}: \:a\cdot (b)/(c)=(a\:\cdot \:b)/(c) \ \textgreater \ (1\cdot \:12)/(6) \ \textgreater \ \mathrm{Apply\:rule}\:1\cdot \:a=a \ \textgreater \ (12)/(6) \ \textgreater \ 2`

Therefore our final answer is

`(25)/(2)`

Hope this helps!

If you meant

`(-5\left((5)/(6)\right))/(-2\left((1)/(6)\right))`

Please let me know as it is a different process but the same answer.