Question

In triangle ABC, a = 18.2, ∠B = 62°, and ∠C = 48°. Find b

Answer 1

to find angle a we do 180-(62+48)=180-110=70
angle a =70
with this we can use the sin rule
a/sin(A)=b/sin(B)=c/sin(C)
since we have side a and angle A and angle b we can do:
18.2/sin(70)=b/sin(62)
then we can times by sin(62)
(18.2/sin(70))*sin(62)=17.1