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What is the factored form of 125a^6-64

User Abigagli
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2 Answers

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(5a^2-4)*(25a^4+20a^2+16) is your answer
User Arley
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5 votes

Answer:


(5a^2-4)(25a^4 + 20a^2+16)

Explanation:


125a^6-64

WE can write 125 as 5^3

Also a^6 = (a^2)^3

64 can be written as 4^3


125a^6-64


5^3(a^2)^3-4^3


(5a^2)^3-4^3

Now we apply a^3 - b^3 formula


a^3 - b^3 = (a-b)(a^2 + ab+b^2)

a= 5a^2 and b = 4

Plug in the values in the formula


(5a^2)^3 - (4)^3 = (5a^2-4)((5a^2)^2 + (5a^2)(4)+4^2)


= (5a^2-4)(25a^4 + 20a^2+16)

WE factored it completely


User Aru Singh
by
8.3k points

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