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The ellipse 14x2+2x+y2=114x2+2x+y2=1 has its center at the point (b,c)(b,c) where

User Dmt
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18x^2 + 2x + y^2 = 1
==> 18(x^2 + x/9) + y^2 = 1
==> 18(x^2 + x/9 + 1/324) + y^2 = 1 + 1/18
==> 18(x + 1/18)^2 + y^2 = 19/18
==> (x + 1/18)^2/19 + (y - 0)^2/(19/18) = 1.

By comparing this to the standard form of an ellipse, the center is at (-1/18, 0).
User Shane Haw
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