Question

What is the specific heat capacity of graphite if it requires 266 j to raise the temperature of 15 grams of graphite by 25°c?

Answer 1

Q= c m T (T is the change in time)

C= Q/(mT)
= 266/(0.015kg x 25)
C=709.33 J/kg.C

Answer 2

`c=0.709\ J/g\ ^(\circ) C`

Step-by-step explanation:

Given that,

Heat required to raise the temperature, Q = 266 J

Mass, m = 15 g

Temperature,
`\Delta T=25^(\circ)\ C`

To find,

The specific heat of graphite.

Solution,

The formula for the specific heat is given by :

`Q=mc\Delta T`

`c=(Q)/(m\Delta T)`

`c=(266\ J)/(15* 25)`

`c=0.709\ J/g\ ^(\circ) C`

So, the specific heat capacity of graphite is
`0.709\ J/g\ ^(\circ) C`. Hence, this is the required solution.