Question

Sergey is solving 5x2 + 20x – 7 = 0. Which steps could he use to solve the quadratic equation by completing the square? Check all that apply. 5(x2 + 4x + 4) = –7 + 20 x + 2 = 5(x2 + 4x) = 7 5(x2 + 4x + 4) = 7 + 20 5(x2 + 4x) = –7 x + 2 =

Answer 1

2,3,4 are the answers on edge

Explanation:

Answer 2

`5(x^2+4x)=7`

Option 2 and 3 is correct.

Explanation:

Case (I).

Given equation is

`5x^2+20x-7=0`

Firstly, we will add of 7 in both sides

`5x^2+20x-7+7=7`

Now, same variable of opposite sign is cancelled

`5x^2+20x=7`

Now, taking 5 common from left side

`5(x^2+4x)=7`

Case (II).

Given equation

`5x^2+20x-7=0`

Firstly, we will add of 7 in both sides

`5x^2+20x=7`

Now, we will add of 20 in both sides

`5x^2+20x+20=7+20`

Now, taking common of 5 from left side

`5(x^2+4x+4)=7+20`

So, The next step on solving completing square is
`5(x^2+4x)=7` and
`5(x^2+4x+4)=7+20`