Question

Which of the equations below could be the equation of this parabola?

Answer 1

A) x=1/6y^2 is the answer

Answer 2

Option A is correct

`x = (1)/(6)y^2`

Explanation:

From the figure, we can see that the equation of the graph is a horizontal parabola.

The equation of the horizontal parabola opens to the right is given by:

`x = a(y-k)^2+h` .....[1]

where:

(h, k) is the vertex of the parabola .

Given that:

(0, 0) = (h, k)

⇒h = k = 0

Substitute in [1] we get;

`x = a(y-0)^2+0`

`x = ay^2`

Therefore, the answer from the given option is
`x = (1)/(6)y^2`