Question

How much would your 20.0 kg dog weigh on Neptune?

Answer 1

F= 6m.m2/r^2

F= (6.673x10^-11)(70)(3.32x10^23)/(2.44x10^6)^2


ANS: F= 260 N=2.60x10^2 N

Answer 2

W=223 N

Step-by-step explanation:

To know the weight of a person,an animal or an object we have the equation:

W=mg

Where:

W: Weight of the person, animal or object.

m: Mass of the person, animal or object.

g: Acceleration of gravity.

In this case we know the mass of the dog m=20.0kg, then in order to find the Weight we need to know g, the acceleration of gravity, in case of the Earth
`g=9.8(m)/(s^(2) )`, but on Neptune g has another value.

`g_(n) =11.15(m)/(s^(2) )`, where
`g_(n)` is the acceleration of gravity on Neptune.

Now, replacing the data:

`W=mg\\ W=20.0kg(11.15(m)/(s^(2) ) )\\ W=223.0 kg(m)/(s^(2) ) \\ W=223.0 N`