Question

What is the work for this question ?

Answer 1

`CA = 2.97516879`

`AB = 6.786871837`

Explanation:

`\tan(B) = (opposite)/(adjacent)`

`\tan(26) = (CA)/(6.1)`

`(6.1) \tan(26) = (CA)/(6.1) (6.1)`

`(6.1) \tan(26) = CA`

`2.97516879 = CA`

`CA = 2.97516879`

`CA \approx3`

`\cos(B) = (adjacent)/(hypotenuse)`

`\cos(26) = (6.1)/(AB)`

`(AB) \cos(26) = (6.1)/(AB) (AB)`

`(AB) \cos(26) = 6.1`

`((AB) \cos(26) )/( \cos(26) ) = (6.1)/( \cos(26) )`

`AB = (6.1)/( \cos(26) )`

`AB = 6.786871837`

`AB \approx6.8`