Question

A garden store has the following miscellaneous flower bulbs in a basket:

6 amaryllis
5 daffodils
3 lilies
4 tulips
A customer bought 4 bulbs from the basket, one of each type of flower. If the next customer selects 1 of the remaining bulbs at random, which is closest to the probability that customer will get a "lily" bulb?

A:36%
B:29%
C:17%
D:14%

Answer 1

D. 14%.

Explanation:

We have been given that a garden store has 6 amaryllis , 5 daffodils , 3 lilies and 4 tulips flower bulbs in a basket.

Since a customer had bought one of each type of flower bulb, so the number of remaining flower bulbs will be:

5 amaryllis , 4 daffodils , 2 lilies , 3 tulips

`\text{Probability}=\frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}`

`\text{Probability of getting a lily bulb}=\frac{\text{Number of lily bulbs}}{\text{All bulbs}}`

`\text{Probability of getting a lily bulb}=(2)/(5+4+2+3)`

`\text{Probability of getting a lily bulb}=(2)/(14)`

`\text{Probability of getting a lily bulb}=0.142857`

Let us convert our answer into percentage by multiplying 0.142857 by 100.

`\text{Probability of getting a lily bulb}=0.142857* 100`

`\text{Probability of getting a lily bulb}=14.2857\%\approx 14\%`

Therefore, the probability that the next customer will get a "lily" bulb is approximately 14% and option D is the correct choice.