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Find the midpoint of the line segment defined by the points: (5, 4) and (−2, 1)

User Mlarsen
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2 Answers

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\bf ~~~~~~~~~~~~\textit{middle point of 2 points }\\ \quad \\ \begin{array}{ccccccccc} &&x_1&&y_1&&x_2&&y_2\\ % (a,b) &&(~{{ 5}} &,&{{ 4}}~) % (c,d) &&(~{{ -2}} &,&{{ 1}}~) \end{array}\qquad % coordinates of midpoint \left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right) \\\\\\ \left( \cfrac{-2+5}{2}~~,~~\cfrac{1+4}{2} \right)\implies \left((3)/(2)~~,~~(5)/(2) \right)\implies \left(1(1)/(2)~~,~~2(1)/(2) \right)
User Chad Decker
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Answer: The mid point of the line segment is (1.5,2.5).

Explanation:

Since we have given that

A (5,4) and B(-2,1) are the end points of the line segment.

We need to find the mid point say 'C':

As we know the formula for "Mid point ":


C=((x_1+x_2)/(2),(y_1+y_2)/(2))\\\\C=(5-2)/(2),(4+1)/(2))\\\\C=((3)/(2),(5)/(2))\\\\C=(1.5,2.5)

Hence, the mid point of the line segment is (1.5,2.5).

User Bond
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