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27 votes
angle RPQ=60angle PQR=qangle QRP=rIn A PQR above, PQ > QR Which of the following must be true?A. PR = PQB. PR < QRC. q = rD. q = 50

angle RPQ=60angle PQR=qangle QRP=rIn A PQR above, PQ > QR Which of the following-example-1
User Raghu Ariga
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2.9k points

1 Answer

9 votes
9 votes

Given the triangle PQR

m∠RPQ = 60

m∠PQR = q

m∠QRP = r

And, PQ > QR

We will check the options:

A) PR = PQ (wrong, there is no information to prove it)

B) PR < QR

From the condition PQ > QR ⇒ m∠QRP > m∠RPQ

So, r > 60

As the sum of the angles = 180

So, r + q = 120

But r > 60

So, q < 60

So, q < r

And as a conclusion: PR < QR and PR < PQ

So, the statement is true

So, the answer will be option B) PR < QR

User AndyDan
by
3.0k points