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What is the equation of a line that passes through the point (6, 1) and is perpendicular to the line whose equation is y=−2x−6y=−2x−6 ?

User Lucas Chwe
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1 Answer

2 votes
Lets get the negative reciprocal of the slope so we get

m = (1)/(2)
Now the equation that is perpendicular is

y = (1)/(2) x + b
Lets solve for b by plugging in the point (x,y)=(6,1)

1 = (1)/(2) (6) + b \\ 1 = 3 + b \\ 1 - 3 = b \\ b = - 2
Now plug that into the equation. So the equation of the line that is perpendicular and
passes through the point (6, 1) is

y = (1)/(2) x - 2
User Linkonabe
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8.2k points
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