Question

Hi I need help with this question and need help to explain them what they ask for In the question, thank you very much

Answer 1

`x=(3)/(10)+\frac{\sqrt[]{91}}{10}i;x=(3)/(10)-\frac{\sqrt[]{91}}{10}i`

Step-by-step explanation

To solve the equation given, we have to apply the quadratic formula:

`x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}`

where a = coefficient of x²

b = coefficient of x

c = constant term

From the equation, we have that:

`a=5;b=-3;c=5`

Therefore, solving for x, we have:

`\begin{gathered} x=\frac{-(-3)\pm\sqrt[]{(-3)^2-4(5)(5)}}{2(5)} \\ x=\frac{3\pm\sqrt[]{9-100}}{10}=\frac{3\pm\sqrt[]{-91}}{10}=\frac{3+\sqrt[]{-1\cdot91}_{}}{10} \\ \Rightarrow x=\frac{3\pm\sqrt[]{91}i}{10} \\ \Rightarrow x=(3)/(10)+\frac{\sqrt[]{91}}{10}i;x=(3)/(10)-\frac{\sqrt[]{91}}{10}i \end{gathered}`

That is the solution to the equation.