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Let cos(−θ)=−3/5 and tanθ>0 . What is the value of sin(−θ)? A. -3/5 B. 4/5 C. -4/5 D. 4/3

Let cos(−θ)=−3/5 and tanθ>0 . What is the value of sin(−θ)? A. -3/5 B. 4/5 C. -4/5 D. 4/3
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3 votes
Let cos(−θ)=−3/5

and tanθ>0 .

What is the value of sin(−θ)?

A. -3/5
B. 4/5
C. -4/5
D. 4/3

User Hitesh Menghani
by
7.9k points

2 Answers

4 votes

Answer: 4/5

Step-by-step explanation: Took the test

User Carlos Mougan
by
8.1k points
6 votes
cos(-x)=cos(x)=-3/5=a/h
sin(-x)=-sin(x)=-o/h=o/5
we know 3^2+4^2=5^2 so
sin(-x)=4/5 its B
User Kim Hyesung
by
8.1k points
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