Question

How do I find the area and premiter of these shapes

Answer 1

The area of the circle is

`A=\pi(r)^2`

The perimeter of the circle is (its circumference)

`P=2\pi(r)`

r is the radius of the circle

Since r = 3 ft, then

`\begin{gathered} A=\pi(3)^2=9\pi ft^2 \\ P=2\pi(3)=6\pi\text{ ft} \end{gathered}`

The area of the triangle is

`A=(1)/(2)bh`

b is the base

h is the height

Since the base is 5 ft, and the height is 5 ft, then

b = 5

h = 5

`A=(1)/(2)(5)(5)=12.5ft^2`

Since the 3 sides of the triangle are equal, then its perimeter is the sum of the 3 sides

`P=5+5+5=15ft`

The area of the square is

`\begin{gathered} A=s* s \\ P=s*4 \end{gathered}`

Since the side of the square is 5 ft

`\begin{gathered} A=5*5=25ft^2 \\ P=5*4=20ft \end{gathered}`