Question

What is the osmotic pressure of a 0.25 m solution of sucrose at 37°c? (r = 0.0821 l⋅atm/k⋅mol)?

Answer 1

`\Pi =6.4atm`

Step-by-step explanation:

Hello,

The osmotic pressure equation is given by:

`\Pi =iCRT`

in this case, sucrose is not ionized, so the van't Hoff factor is 1; thus, one computes the osmotic pressure directly:

`\Pi =1(0.25(mol)/(L) )(0.0832(atm*L)/(mol*K))(37+273.15)K\\\Pi =6.4atm`

Best regards.

Answer 2

osmotic pressure is minimum pressure which need to applied to a solution to prevent inward flow of its pure solvent across a semipermeable membrane.
osmotic pressure =cRT
c=concentration =0.25M or 0.25 mol/l
R=gas constant=0.0821 atm/mol.k
T=temperature=37 +273=310k
osmotic pressure is therefore
0.25 mol/L x0.0821L.atm/mol.k x 310k=6.36atm