Question

Alan sells custom made kites online. He makes a flat profit of $20 per kite, but he pays $20 per day for his website. Write an inequality that gives the number of kites Alan needs to sell to make at least $900 per week?

Answer 1

52 kites

Explanation:

We are given that

Profit of one kite=$20

He pays per day for his website=$20

Number of days in 1 week=7

Allen needs to sell to make atleast in 1 week=$900

We have to write an inequality that gives the number of kites.

Let x be the number of kites.

According to question

`20* x-20* 7 \geq 900`

`20x-140 \geq 900`

adding 140 on both sides

`20x+140-140\geq 900+140`

`20x\geq 1040`

Divide by 20 on both sides

`(20x)/(20)\geq (1040)/(20)`

`x\geq 52`

`x\geq 52`

Hence, Allens need to sell atleast 52 kites.

Answer 2

To pay website Alen needs to make 1 kite a day that is 7 kites.
To earn at least 900$ per week he needs to make 900$/20$=45kites
900/20+7=52 kites. Alen need to make at least 52 kites a week to earn at least 900$.