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Your normal force on a 17.7kg block. The block is on a level surface and a force of 175N is exerted on it at an angle of 35.8 below the horizontal.

User Ondrej Stocek
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1 Answer

12 votes
12 votes

Given that the mass of the block is m = 17.7 kg

The force exerted on it is F = 175 N.

The angle is


\theta=35.8^(\circ)

We have to find the normal force.

The normal force can be calculated by the formula,


N=mg-F\sin \theta

Here, g = 9.81 m/s^2 is the acceleration due to gravity.

Substituting the values, the normal force will be


\begin{gathered} N=17.7*9.81-175sin35.8^(\circ) \\ =173.64-102.36 \\ =71.28\text{ N} \end{gathered}

Thus, the normal force is 71.28 N

User SubSevn
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