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If 8a + 3b + 2c = 3, what is 64a+24b+16c?

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Low Flying Pelican · Answer 1 · 2018-06-09T22:22:12+0000

Answer:

64a+24b+16c = 24

Explanation:

Given : 8a + 3b + 2c = 3

We have to find the value of 64a+24b+16c

Consider 64a+24b+16c

Taking 8 common from each term , we have,

64a+24b+16c = 8(8a + 3b + 2c)

Also, given 8a + 3b + 2c = 3

Then , 64a+24b+16c = 8(8a + 3b + 2c)

= 8(3)

Simplify , we have,

= 24

Thus, 64a+24b+16c = 24

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