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Can you please help me solve 4^(2x+1)=3^(x-2) for x?
Thank you!

User Orlee
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1 Answer

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In order to solve the equation we should take the natural logarithm of both sides of the equation (the goal is to remove the variable from the exponent)ln(4^(2x+1))=ln(3^(x−2))
(2x+1)ln(4)=(x-2)ln(3)
2x*ln(4)+ln(4)=xln(3)-2ln(3)
2x*ln(4)-xln(3)=-ln(4)-2ln(3)
x(2ln(4)-ln(3))=-ln(4)-2ln(3)
x=-ln(4)-2ln(3)/(2ln(4)-ln(3))

User Iqbal Jan
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