Question

11. Calculate the concentration of a 600.0 mL solution that contains 2.50 g of CaCO3.

Answer 1

The concentration of the solution is 0.042M

Step-by-step explanation

Given that;

The volume of the solution is 600mL

The mass of the solute is 2.50 g

To find the concentration of the solution, follow the steps below

Step 1; Find the number of moles of CaCO3 using the below formula

`\text{ Mole }=\text{ }\frac{\text{ mass}}{\text{ molar mass}}`

Recall, that the molar mass of CaCO3 is 100.0869 g/mol

`\begin{gathered} \text{ mole }=\text{ }(2.5)/(100.0869) \\ \text{ mole }=\text{ 0.0250 mol} \end{gathered}`

The number of moles of the solute is 0.0250 mol

Step 2; Convert the volume of the solution to L from mL

Recall, that 1mL is equivalent to 0.001L

`\begin{gathered} \text{ Let v represents the volume of the solution is Liters} \\ \text{ 1 mL }\rightarrow\text{ 0.001L} \\ 600mL\rightarrow\text{ vL} \\ \text{ Cross multiply} \\ \text{ 1mL}*\text{ vL}=\text{ 600mL}*\text{ 0.001L} \\ \text{ Isolate v} \\ \text{ vL }=\frac{600\cancel{mL}*0.001L}{1\cancel{mL}} \\ \text{ v }=\text{ 600}*\text{ 0.001} \\ \text{ v }=0.6L \end{gathered}`

The volume of the solution in L is 0.6L

Step 3; Find the concentration of the solution using the below formula

`\begin{gathered} \text{ molarity}=\text{ }\frac{moles\text{ of solute}}{vol.\text{ of solution}} \\ \text{ molarity }=\text{ }(0.0250)/(0.6) \\ \text{ molarity }=0.042\text{ M} \end{gathered}`

The concentration of the solution is 0.042M