Question

A fitness center currently has 320 members. Monthly memberships fees are $45. The manager of the fitness center has determined that each time the membership increases by $5, approximately 10 members leave and go to a different gym.

Write a equation that can be used to find the revenue of the fitness center in dollars,y, after x price increases of $5

Answer 1

y = -50x2 + 1,150x + 14,400

Explanation:

I took the test it was right

Answer 2

The required equation :

`y=(320-10x)(45+5x)=14400+1150x-50x^2`

Explanation:

Given : A fitness center currently has 320 members. Monthly memberships fees are $45. The manager of the fitness center has determined that each time the membership increases by $5, approximately 10 members leave and go to a different gym.

To write : A equation that can be used to find the revenue of the fitness center in dollars,y, after x price increases of $5.

Solution :

Revenue is defined by the amount or price during specific period.

Let x be the number of months,

y be the revenue of the fitness center.

The number of members in the fitness center is 320 but after increasing $5 10 members leave.

So, the total member after increment in x months are
`320-10x`

Monthly memberships fees are $45.

The manager of the fitness center has determined that each time the membership increases by $5.

The price of monthly membership after increment is
`45+5x`

So, The equation which gave the revenue of the fitness center is

`y=(320-10x)(45+5x)`

`y=14400+1600x-450x-50x^2`

`y=14400+1150x-50x^2`