Question

Point A is located at (2, 6) and point B is located at (18, 12).

What point partitions the directed line segment ​ AB¯¯¯¯¯ ​ into a 2:3 ratio?



(8/2/5, 8/2/5)

(10/1/2, 10/1/2)

(11/3/9, 9/3/5)

(14/1/2, 12)

Answer 1

The answer is:

A - (8 2/5 , 8 2/5)

Eight and two fifths for x and y.

Have an amazing day.

Answer 2

from A-->B in a 2:3 ratio means that it's 2/(2+3) of the way up AB
So 2/5 of the x of AB = 2/5×(18-2) = 2/5 (16)
= 32/5 = 6 2/5 + the original x of A (2) = 8 2/5
2/5 of the y of AB = 2/5×(12-6) = 2/5 (6)
= 12/5 = 2 2/5 + the original y of A (6) = 8 2/5
Therefore the answer is:
(8 2/5, 8 2/5)