probability of an event = (required outcome) / (total possible outcome)
Also if two events A and B are independent,
P(AnB) = P(A) x P(B)
In this case,
total possible outcome = 7 (Since there are 7 cards)
The number of cards marked 'O' is 1.
So the probability of picking 'O' first = 1 / 7
After picking O and not putting it back,
total possible outcome = 7 - 1 =6
and the number of Ts remain 2
So the probability of picking T second = 2 / 6 = 1 / 3
The probability of picking O first is independent of the probability of picking T second
Hence,
The probability of picking O first and T second is