Question

13. A force of 150 N acts on a 4 Kg bowling ball for 0.2 s. Calculate the change in velocity.

Answer 1

The change in velocity Δv for an object that accelerates at a constant rate a during a time interval Δt is given by the equation:

`\Delta v=a\cdot\Delta t`

On the other hand, if a force F acts on an object with mass m, the object will be accelerated by the force at a rate a given by:

`a=(F)/(m)`

Replace F=150N and m=4kg to find the acceleration of the bowling ball:

`a=(150N)/(4kg)=37.5(m)/(s^2)`

Next, replace a=37.5 m/s^2 and Δt=0.2s to find the change in velocity of the bowling ball:

`\Delta v=(37.5(m)/(s^2))(0.2s)=7.5(m)/(s)`

Therefore, the change in velocity is 7.5m/s.