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15 votes
Solve for x. Write both solutions, separated by acomma.6x² + 7x+2=0

User EduLopez
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1 Answer

20 votes
20 votes

Explanation

We are given the following:


6x^2+7x+2=0

We are required to solve the equation above.

Using the quadratic formula, we have:


\begin{gathered} If\text{ }ax^2+bx+c=0,\text{ }then \\ x=(-b\pm√(b^2-4ac))/(2a) \end{gathered}
\begin{gathered} 6x^2+7x+2=0 \\ where \\ a=6,b=7,c=2 \\ x=(-7\pm√(7^2-4(6)(2)))/(2(6)) \\ x=(-7\pm√(49-48))/(12) \\ x=(-7\pm√(1))/(12)=(-7\pm1)/(12) \\ x_1=(-7+1)/(12),x_2=(-7-1)/(12) \\ x_1=(-6)/(12),x_2=(-8)/(12) \\ x_1=(-1)/(2),x_2=(-2)/(3) \end{gathered}

Hence, the answer is:


x_(1)=(-1)/(2), x_(2)=(-2)/(3)

User Moeseth
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