Question

Help with the rest of these equations please

Answer 1

`24x + y = 79 \\ y = 3x - 2 \\ substituting \: the \: above \: value \: of \: y \: \\ 24x + 3x - 2 = 79 \\ 27x = 79 + 2 \\ 27x = 81 \\ x = (81)/(27) \\ x = 3 \\ now \: y = 3x - 2 \\ y = 3 * 3 - 2 \\ y = 9 - 2 \\ y = 7 \\ x = 3 \\ y = 7 \\ x + 2y = 10 \\ x = y + 1 \\ y + 1 + 2y = 10 \\ 3y + 1 = 10 \\ 3y = 10 - 1 \\ 3y = 9 \\ y = (9)/(3) \\ y = 3 \\ x + 2y = 10 \\ x + 2 * 3 = 10 \\ x + 6 = 10 \\ x = 10 - 6 = 4 \\ x = 4 \\ y = 3`