Question

The sum of three consecutive even numbers is 60. what is the smallest of these numbers?

Answer 1

The smallest number is unknown. We can call it "a."

Now the sum would be (a) + (a+2) + (a+4) = 60

3a + 6 = 60

3a = 54

a = 18

So the smallest number is 18. We can verify it:

18 + 20 + 22 = 60

Final answer: 18