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Given ΔABC, AB = BC = AC . Area of ΔABC = 25 sqrt3 /4 cm. Find the perimeter of ΔABC.
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Given ΔABC, AB = BC = AC . Area of ΔABC = 25 sqrt3 /4 cm. Find the perimeter of ΔABC.

User John Vrbanac
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1 Answer

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This is an equilateral triangle of height a√3/2 where a is the side length. So the area is ½a.a√3/2=a²√3/4.
So a²=25 and a=5cm. Therefore the perimeter is 3a=15cm.
User Ecc
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